Vidit Gujrathi qualifies to the Freestyle Grand Slam Tour 2025 Paris
Vidit Gujrathi defeated Richard Rapport in the Finals of Freestyle Grand Slam Tour 2025 Play-in to qualify to the Paris leg. He defeated the 17th world champion Ding Liren (CHN) by 1.5-0.5 in Round of 16. Then he won against compatriot Pranesh M by same score in the Quarterfinals. In the Semifinals, Vidit crushed M Amin Tabatabaei by winning it 2-0. In the Finals, Vidit won the match 1.5-0.5 to secure his place in the Paris leg which will take place from 7th to 14th April next month. The total prize fund for the play-in was US$ 50000. The top three prizes were US$ 10000, 9000 and 8000 each. Vidit joins Magnus Carlsen, Hikaru Nakamura, D Gukesh, Fabiano Caruana, Arjun Erigaisi, R Praggnanandhaa, Alireza Firouzja, Ian Nepomniachtchi, Hans Niemann, Maxime Vachier-Lagrave and Vincent Keymer. There will be four Indians for the upcoming Paris leg. Photo: Anmol Bhargav
Four Indians in the Paris leg
There will be four Indians in the Paris leg of Freestyle Grand Slam Chess Tour 2025. It will take place from 7th to 14th April 2025. They are - GM D Gukesh, GM Arjun Erigaisi, GM R Praggnanandhaa and GM Vidit Gujrathi.
Arjun Erigaisi wins Freestyle Friday three in-a-row, Mitrabha Guha stuns Magnus Carlsen
Arjun Erigaisi has won Freestyle Friday online tournament for the third consecutive time. He scored 10/11, finishing a full point ahead of the rest. The inaugural and reigning Commonwealth Rapid Gold medalist, Mitrabha Guha defeated Magnus Carlsen (NOR) to finish sixth scoring 8.5/11. Mitrabha finished ahead of D Gukesh (10th), S L Narayanan (13th), B Adhiban (17th) and R Praggnanandhaa (18th).
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